微软暑期实习笔试题

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微软暑期实习笔试题

  发信人: loccs(short), 信区: JobForum

微软暑期实习笔试题

  发信站: 饮水思源 (2012年04月07日18:53:56 星期六)Choose部分是我自己做的答案,非标准答案.有些题目选项记不起来了,非常抱歉.

  1. Selection sort 80 items, after 32 iterations, how many positions of items are determined?

  Choose:32。

  2. Which is used in sync process//thread in operation system?

  A. Mutex                  B.mailbox          C.Semaphore          D.local procedure callChoose: AC

  3. Size of a stack is 5, input is a sequence 1, 2, …, 7, which is possible output?

  A. 1234567        B. 7654321        C.5643721        D. 1765432        E. 3217564Choose: AC

  4. 010111001 * 011001 + 1101110 = ?

  A. 0001010000111111        B. 0101011101110011        C. 0011010000110101Choose: A

  5. What is the output of the follow code?

  void main(int argc, char* argv[]) {

  int i = 11;

  int const *p = &i;

  p++;

  cout<<*p<

  A. 11        B. 12        C. Garbage value        D. Comipler error        E. None of aboveChoose: C

  6. Which code is correct?

  C. vectorf() {

  vectorv(3);

  return v;

  }

  E. None of above

  Choose: C

  7. Which number has difference 78633 after 180-degree rotation?

  A. 60918                B.91086                C. 18609                D. 10968                E.86901Choose: D

  8 Which statement is true?

  A. Inorder and preorder can determine a Binary treeB. Postorder and preorder can determine a Binary treeC. For almost sorted array, Insertion sort is more efficient than QuicksortD. If T(n)=2T(n/2)+&#8854;(n), Then T(n)=&#8854;(nLogn)E. none of above

  Choose: ACD

  9. Which statement is true?

  A. Insertion and buble sort are not effient for large data setsB. The complexity of Quick Sort is O(n2) in worst caseC. It is needed 6 swap operations to sort sequence 7,6,5,4,3,2,1(ascending) by Selection sortD. Heap sort has two operations: Insertion and root deletionE. None of above

  No choose

  12. The output of the following code is 0 20 1 20, what are the type of a and b?

  class Test{

  ____ int a;

  ____ int b;

  Test(int _a, int _b) {a = _a; b=_b;}

  }

  void main() {

  Test t1(0, 0), t2(1,1);

  t1.b = 10;

  t2.b = 20;

  cout<

  A. static/const        B. const/static        C. __/static        D. const static/static        E. None ofabove

  Choose: C

  13. A 3-order B-tree has 2047 key words, what is the maximum height?

  A. 11          B. 12           C. 13           D. 14no choose

  14. Which can be used both to variable and function?

  A. static        B. virtual                C. extern        D. inline        E. constChoose: ACE

  15. What is the output of the follow code?

  char * f(char *str, char ch) {

  char *it1 = str;

  char *it2 = str;

  while(*it2 != \0) {

  while(*it2 == ch)

  {

  it2++;

  }

  *it1++ = *it2++;

  }

  return str;

  }

  int main(int argc, char* argv[]) {

  char *a = new char[10];

  strcpy(a, "abcdcccd");

  cout<

  return 0;

  }

  A. abdcccd        B. abdd        C. abcc        D. abddcccd        E. Access violationChoose: D

  16. What is the complexity of the result call of power(b, e) in the follow code?

  int power(int b, int e) {

  if(e==0) return 1;

  if(e%2 == 0) return power(b*b, e/2);

  return b*power(b*b,e/2);

  }

  A. logarithmic                B. linear        C. quadratic        D. exponenticalChoose: A

  17. Take 2 cards from one full poker(52 cards, 26 red and 26 black) and half poker each, what is the probability of the event that two cards are both red?

  A. 1/2,1/2        B. 25/102,12/50        C. 50/51, 24/25        D. 25/51,12/25        E. 25/51,1/2Choose: B

  18. How many kinds of output of stack with the input 1,2,…,n?

  B. C_2n^n-C_2n^(n+1)                C. ((2n)!)/(n+1)n!n!        D. n!        E. noneChoose: C

  19. What is the minimum time and space complexity to compute the Largest Increased Subsequence(LIS) of array?

  A. N^2,N^2           B. N^2,N                   C. NlogN,N            D. N, N        E. N,CChoose: C

  20. What is the output of the follow code?

  struct Item{

  char c;

  Item *next;

  };

  Item* f1(Item* x){

  Item *prev = NULL;

  Item *curr = x;

  while(curr) {                Item *next = curr->next;curr->next = prev;

  prev = curr;

  curr = next;

  }

  return prev;

  }

  void f2(Item *x){

  while(x){

  cout

  x = x->next;

  }

  }

  int main(int argc, char* argv[]){

  Item *x, d = {d, NULL}, c = {c, &d}, b = {b, &c}, a = {a, &b};x = f1(&a);

  f2(x);

  return 0;

  }

  Choose: dcba


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